Selecting a Compact Electric Cylinder: DRLII Series

Selection Method

(1) Confirming the Required Specifications

Confirm the required specifications for the equipment.

(1) Confirming the Required Specifications
Load mass
m = 5 [kg]
Positioning Distance
L = 40 [mm]
Positioning Time
T = Within 1.5 seconds
Drive Direction
Vertical
Stopping Accuracy
± 0.01 mm

(2) Tentative Selection of Electric Actuators

The following electric actuator is tentatively selected based on the required specifications.

Product Name
DRL42G-04A2P-KD
Lead
2 mm
Types of Ball Screws
Rolled Ball Screw
Resolution
0.04 mm
Power Supply Input
24 VDC

(3) Confirming the Positioning Time

Check whether the actuator can perform the necessary positioning within the specified time. This can be done by obtaining a rough positioning time from the graph or by obtaining a fairly accurate positioning time by calculation. Each of the confirmation procedures is explained below.
The actual operating time is subject to a small margin of error, so use the calculation only as a reference.

Obtaining From a Graph

Use the graph to confirm the positioning time necessary for a positioning distance of 40 mm.

Obtaining From a Graph

The graph above shows that the load can be positioned over a positioning distance of 40 mm within 1.5 seconds.

If the positioning time requirement is not satisfied, select a different model.

Using Formula Calculations

Confirm operation conditions
Please check the following conditions:
Positioning distance, starting speed, acceleration, and operating speed

From the operation conditions above, confirm whether the drive pattern is a triangular drive or trapezoidal drive
Calculate the maximum speed of triangular drive from the positioning distance, starting speed, acceleration and operating speed. If the calculated maximum speed is equal to or below the operating speed, the operation is considered a triangular drive. If the maximum speed exceeds the operating speed, the operation is considered a trapezoidal drive.

\(\begin{align} V_{Rmax} &= \sqrt{ \frac{2 \cdot a_1 \cdot a_2 \cdot L}{a_1 + a_2} \cdot 10^3 + V_{S^2}} \\[5pt] V_{Rmax} & \leqq V_R \rightarrow \text{Triangular Drive} \\[5pt] V_{Rmax} & \gt V_R \rightarrow \text{Trapezoidal Drive}\end{align}\)

Calculate the positioning time
[In the case of trapezoidal drive]

\(\begin{align}T &= T_1 + T_2 + T_3 \\[5pt] & = \frac{V_R - V_S}{a_1 \times 10^3} + \frac{V_R - V_S}{a_2 \times 10^3} + \frac{L}{V_R} - \frac{\left(a_1 + a_2 \right) \times \left(V_{R^2} - V_{S^2} \right)}{2 \times a_1 \times a_2 \times V_R \times 10^3} \end{align}\)

[In the case of triangular drive]

\(\begin{align}T &= T_1 + T_2 \\[5pt] & = \frac{V_{Rmax} - V_S}{a_1 \times 10^3} + \frac{V_{Rmax} - V_S}{a_2 \times 10^3} \end{align}\)
In the case of triangular drive
VRmax
Maximum Speed Calculated for Triangular Drive [mm/s]
VR
Operating Speed [mm/s]
Vs
Starting Speed [mm/s]
L
Positioning Distance [mm]
a1
Acceleration [m/s²]
a2
Deceleration [m/s²]
T
Positioning Time [s]
T1
Acceleration Time [s]
T2
Deceleration Time [s]
T3
Constant Speed Time [s]